Center 10
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How do I Find the center of the hyperbola (1/10)(x - 1)^2 - (y - 1)^2 = 1?
Sorry for adding this but in the same equation, for example, what would the foci, the length of one of the two axis, and the two asymptotes be for the hyperbola then?
Any answer would help a ton,
Thank you!
(1/10)(x-1)² - (y-1)² = 1
First put the equation into vertex form:
(x-1)²/10 - (y-1)²/1 = 1
The x term is positive, indicating a horizontal hyperbola.
General equation for a horizontal hyperbola:
(x-h)²/a² - (y-k)²/b² = 1, with
center: (h, k)
eccentricity c = √(a²+b²)
foci: (h±c, k)
length of transverse axis = 2a
length of conjugate axis = 2b
slopes of asymptotes: ±b/a
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