Bullet 17
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A 17.0 g rubber bullet hits a wall with a speed of 200 m/s.?
If the bullet bounces straight back with a speed of 130 m/s, what is the magnitude of the change in momentum of the bullet?
What is the direction of the change in momentum of the bullet?
Let the positive direction be away from the wall
So p(i) = m*vi = 0.0170kg*(-200m/s) = -3.4kg-m/s
p(f) = m*vf = 0.0170*130 = 2.21kg -m/s
So Δp (change in momentum) = p(f) - p(i) = 2.21 - (-3.4) = 5.61kg-m/s
and it is directed away from the wall


US $60.00







































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